Jon Moxley signs with AEW

Following his debut at AEW’s Double or Nothing event on Saturday night, All Elite Wrestling has announced that Jon Moxley, formerly known as Dean Ambrose from WWE, has signed a multi-year deal with the company.

Moxley was last seen wrestling with WWE on April 21 with this final match being a victory as a member of The Shield. It was announced in January the Ambrose would not be renewing his contract and would be leaving.

AEW passed along the following press release:

AEW Signs Superstar Jon Moxley to Multi-Year Deal
— Mox Makes Presence Known at DOUBLE OR NOTHING —

Las Vegas, NV (May 25, 2019) – In a night jam-packed with intense showdowns and incredible clashes, AEW rocked the wrestling world even further with a surprise appearance by international wrestling star Jon Moxley to close out DOUBLE OR NOTHING.

AEW confirmed tonight that it has officially signed Moxley to a full-time, multi-year agreement effective immediately. Moxley, who was twice voted as Most Popular Wrestler of the Year by Pro Wrestling Illustrated, will make his in-ring debut at FYTER FEST in Daytona Beach, FL, on Saturday, June 29.

“The arrival of Jon Moxley at Double or Nothing was the perfect ending to one of the most important nights in wrestling history,” said Tony Khan, President and CEO of AEW. “There was no better way to conclude an evening of new beginnings than with the introduction of the best free agent wrestler in the world. The chaotic scene that unfolded in the closing moments of Double or Nothing was emblematic of the unpredictability and explosiveness that Jon Moxley will bring to AEW. We’re very proud that Jon has signed a multi-year contract, and he is officially on the All Elite Wrestling roster!”